Analog and Op-Amps

Model class: Exact ideal relationship

Inverting op-amp designer

Calculate ideal inverting op-amp signal gain, noise gain, and output voltage from resistor values and input.

Interactive engine

Start with the stated conditions.

Values stay in this browser. Choose a representative scenario, then calculate deliberately.

Example ready

Calculate to inspect the result.

The result will identify the direct answer, assumptions, and any warning that changes the next decision.

Next decision:Summing amplifier designer

Assumptions to check

  • The entered inverting-op-amp values represent the stated operating condition.
  • This exact ideal relationship is evaluated in the declared lumped or first-pass model.
  • A inverting-op-amp calculation is not a component qualification or safety approval.

What this inverting-op-amp calculation establishes

Calculate ideal inverting op-amp signal gain, noise gain, and output voltage from resistor values and input. The useful result is the stated electrical quantity and the decision it supports, not an unstated claim about a finished product. This engine keeps the governing relationship visible so an input, unit, condition, or model boundary can be reviewed before a value becomes a component or layout choice.

Ideal signal gain is minus the feedback resistance divided by the input resistance; noise gain is one plus that same ratio. Treat the number as a first-pass result for the declared operating point. When a source, load, temperature, frequency, waveform, component tolerance, or measurement condition changes, repeat the calculation at the relevant corner rather than assuming the nominal answer persists.

Worked decision context

A 10 kΩ input resistor with a 100 kΩ feedback resistor gives -10 V/V signal gain and 11 V/V noise gain. That example verifies the equation and illustrates the scale of the result, but it does not select a part by itself. Compare the result with available values, ratings, tolerance bands, and the receiving circuit or physical environment before implementation.

Use the primary output to identify the binding constraint. If it leaves little margin, document which input dominates and use selected-part data, a higher-fidelity model, simulation, or measurement. This is especially important when a small numerical difference changes a thermal, timing, noise, or reliability decision.

Limits and validation handoff

It omits input bias current, offset voltage, finite open-loop gain, source resistance, and output headroom. The calculation does not silently include omitted parasitics, installation conditions, manufacturing variation, or product policy. Those conditions can be decisive even when the arithmetic is exact for the selected model.

Record inputs, units, model assumptions, and the intended decision with the result. Verify the leading risk against the selected component data sheet and a representative measurement when the circuit has consequential energy, high voltage, safety, compliance, or reliability requirements.

Common mistakes

  • Treating the inverting-op-amp result as a guaranteed operating limit rather than a first-pass exact ideal relationship estimate.
  • Mixing a data-sheet value measured under one condition with this inverting-op-amp calculation performed at another.
  • Selecting a component before checking the boundary this calculation names: it omits input bias current, offset voltage, finite open-loop gain, source resistance, and output headroom.

Model limit and handoff

Keep the entered inverting-op-amp conditions with the calculation, then validate the binding limit using the selected component, physical implementation, and representative operating corner.

FAQs

Is this inverting-op-amp result sufficient to approve a design?

No. It applies exact ideal relationship reasoning to the entered inverting-op-amp values and names the checks that still need selected-part data, a higher-fidelity model, or measurement. It omits input bias current, offset voltage, finite open-loop gain, source resistance, and output headroom.

What does this inverting-op-amp calculator assume that could make the result wrong?

Ideal signal gain is minus the feedback resistance divided by the input resistance; noise gain is one plus that same ratio. If the entered values do not match the real operating condition, the result no longer describes the actual circuit.

Where should this inverting-op-amp result go next?

Compare this inverting-op-amp result with Selecting an op-amp from the signal envelope, then use the stated next decision below the calculator to move from this first-pass number toward an implementation.